ii) 4a²b²c - 12abc plz send answer
Answers
Answered by
2
Answer:
♡ hope it helps uH ♡
Answered by
0
Answer:
ANSWER
4a2+9b2+c2−12ab−6bc+4ac
=(2a)2+(3b)2+(1c)2−2(2a)(3b)−2(3b)(1c)+2(2a)(1c)
=(2a+3b−c)2
Similar questions