Question

ii. 4b2 + 5bc, -2b2 – 2bc – 2z2 and 2bc + 4c2 what is the sum

Answer 1

Answer:

$4 {b}^{2} + 5bc + ( - 2b {}^{2} - 2bc - 2 {z}^{2} ) + (2bc + 4 {c}^{2} ) \\ \\ 4b {}^{2} + 5bc -2b {}^{2} - 2bc - 2z {}^{2} + 2bc + 4c {}^{2} \\ \\ 4b {}^{2} - 2b {}^{2} + 5bc - 2bc + 2bc - 2z {}^{2} + 4 {c}^{2} \\ \\ 2b {}^{2} + 5bc - 2z {}^{2} + 4c {}^{2}$

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