Question

கழிக்க "(ii) " 4x/(x^2-1)-(x+1)/(x-1)

Answer 1

Answer:

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Explanation:

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Answer 2

கழிக்க  $\frac{4 x}{x^{2}-1}-\frac{x+1}{x-1}$

தீர்வு:

கொடுக்கப்பட்டது  $\frac{4 x}{x^{2}-1}-\frac{x+1}{x-1}$  

$x^{2}-1=(x+1)(x-1)$

= $\frac{4 x}{(x+1)(x-1)}-\frac{x+1}{x-1}$  

$\frac{4 x-(x+1)^{2}}{(x+1)(x-1)} \\=\frac{4 x-x^{2}-2 x-1}{(x+1)(x-1)}$

= $\frac{-x^{2}+2 x-1}{(x+1)(x-1)}$

= $\frac{-\left(x^{2}-2 x+1\right)}{(x+1)(x-1)}$

= $\frac{-(x-1)(x-1)}{(x+1)(x-1)}$

= $\frac{1-x}{(x+1)}$

= $\frac{1-x}{1+x}$

விடை: $\frac{1-x}{1+x}$