Question

(ii) 4y2 - 4y + 1
answer it using the appropiate identity​

Answer 1

Answer:

4y² - 4y + 1

To factorise this algebraic term, we will use the algebraic identity:-

(a-b)² = a² - 2ab + b²

4y² - 4y + 1

(2y)² - 2(2y)(1) + (1)²

a = 2y

b = 1

(2y - 1)²

= (2y - 1)(2y - 1) Ans

VERIFY:

(2y - 1)(2y - 1) = 4y² - 4y + 1

(2y - 1)² = 4y² - 4y + 1

[2y]² - 2(2y)(1) + (1)² = 4y² - 4y + 1

[4y² - 4y + 1] = [4y² - 4y + 1]

LHS= RHS

Hence, verified

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