Question

(ii) 4yz (z^2 +6z–16) ÷2y(z+8)
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Answer 1

$\mathfrak{\huge{\red{QUESTION}}}$

DIVIDE

= 4yz (z² + 6z - 16) by 2y(z+8)

$<font color = "blue"><marquee>ANSWER IN ATTACHEMENT ALSO </font color = "blue"></marquee>$

First Multiply 4yz with (z² + 6x -16) and 2y with (z + 8)

= 4yz(z² + 6x - 16)

= 4yz³ + 24yz² - 64yz

And

2y(z +8)

= 2yz + 16y

Now dividing .. in attachement

FINALLY

$\mathfrak{\huge{\red{ANSWER}}}$

= 2z² - 4z