Question

ii) '5x+3y=11 3x+5y=13' in elimination method​

Answer 1

Answer:

2x - 5y = -7 Equation 1

5x - 3y = 11 Equation 2

take whichever variable you want to eliminate and multiply the coefficient of equation 2 to equation 1, then multiply the negative of the coefficient of equation 1 to equation 2 and add them

5(2x - 5y) = 5(-7)

-2(5x - 3y) = -2(11)

_____________

10x - 25y = -35

-10x + 6y = -22

_____________

-19y = -57

y = 3

You can substitute that back in to either equation and solve for the remaining term but because you are asking about elimination I'll do the same process as before but this time to the y variable

-3(2x - 5y) = -3(-7)

5(5x - 3y) = 5(11)

______________

-6x + 15y = 21

25x - 15y = 55

_____________

19x = 76

x = 4

your answer is: (4,3)

plug those values back into both equations to check:

2(4) - 5(3) = -7

8 - 15 = -7

5(4) - 3(3) = 11

20 - 9 = 11

Answer 2

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