(ii) 99x + 101y = 499xy 101x + 997 = 501xy. by substitution method
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Step-by-step explanation:
99x+101y= 499 eq1
101x+99y=501. eq2
add equ1 and 2
200x+200y=1000
so divide with 200
x+y=5. eq3
same way sub eq1 and 2
-2x+2y =-2
divide with -2
x-y=1. eq4
now solve eq3 and 4 by substitution method
from eq4
x=1+y
put that in 3
1+y+y=5
2y=4
y=2
put y values in eq4
x-2=1
x=3
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Answer:
first write right of page and then write left side page
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