Question

(ii) (9p - 5q) + 180pq = (9p+5q)2​

Answer 1

Answer:

$(9p - 5q)^{2}$ + 180pq = $(9p+5q)^{2}$ ; LHS = RHS ; problem is verified.

Step-by-step explanation:

$(9p - 5q)^{2}$ + 180pq = $(9p+5q)^{2}$

$(9p+5q)^{2}$  - $(9p - 5q)^{2}$ = 180pq

(81$p^{2}$ + 25$q^{2}$ + 90pq) - (81$p^{2}$ + 25$q^{2}$ - 90pq) = 180pq

(81$p^{2}$ + 25$q^{2}$ ) - (81$p^{2}$ + 25$q^{2}$) + 90pq + 90pq = 180pq

90pq + 90pq = 180pq

180pq = 180pq

hence the problem is solved.

LHS = RHS