Math, asked by subhodipmajhi2008, 1 month ago

(ii)
(a + 3) (a + 6) find the product using suitable identity​

Answers

Answered by shradhaverdhan
1

Answer:

a=18/11

Step-by-step explanation:

(a+3)(a+6)

(a+3)(a+6)=0

2a+6a+3a+18=0

Transpose 18

2a+6a+3a= -18

11a= -18

Transpose 11

a= -18/-11

Cancel the signs

a=18/11

Answered by snavpreet85660
1

Answer:

Value of a can either be -3 or -6

Step-by-step explanation:

(a+3)(a+6)

(a)²+(3+6)a+(3)(6)---------------[Identity=> (x+a)(x+b)=x²+(a+b)x+ab]

a²+9a+18

By splitting the middle term, we get

a²+6a+3a+18=0

a(a+6)+3(a+6)=0

(a+3)(a+6)=0

a+3=0 ; a+6=0

a=-3 ; a=-6

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