(ii) A (6,-4), B (-2,-4), C (2,10)
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Let A(1,2), B(4,y),C(x,6) and D(3,5) are the vertices of a parallelogram ABCD
.AC and BD are the diagonals .
O is the midpoint of AC and BD.
If O is the mid-point of AC ,then the coordinates of O are =(21+x,22+6)=(2x+1,4)
If O is the mid-point of BD then coordinates of O are (24+3,25+y)=(27,25+y)
Since both coordinates are of the same point O
∴21+x=27
⇒1+x=7
⇒x=7−1=6
∴25+y=4
⇒5+y=8
⇒y=8−5=3
Hence x=6 and y=3.
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