(ii) A ABC is an equilateral triangle.
A ACD is an isosceles triangle with AC = CD, ZCAD = 5x + 15°. Find x.
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Given A ABC is an equilateral triangle. A ACD is an isosceles triangle with AC = CD, angle CAD = 5x + 15°. Find x
- Angle ABC is an equilateral triangle.
- Angle ACD is an isosceles triangle
- Also AC = CD
- Given angle CAD = 5x + 15 at point C
- So angle ABC = angle ACB = 60 degree
- We have at point C we get
- So 5x + 15 + 60 = 180
- 5x + 75 = 180
- 5x = 180 – 75
- 5x = 105
- Or x = 105 / 5
- Or x = 21 degree
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https://brainly.in/question/2835904
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