Question

(ii) a + b3 + c3 – 3abc
if a = - 1, b = 2, c = 3​

Answer 1

Answer:

53

Step-by-step explanation:

-l+(2)3+(3)3-3(-1)(2)(3)

Answer 2

Correct Question:

Find the solution of the expression, a + b³ + c³ - 3abc

if a = -1, b = 2, c = 3

Solution:

= $\sf{a+b^3+c^3-3abc}$

[Substituting the values]

= $\sf{-1+2^3+3^3-(3\times-1\times2\times3)}$

= $\sf{-1+8+9-(-18)}$

= $\sf{-1+8+9+18}$

= $\sf{34}$

Therefore the solution of the expression, a + b³ + c³ - 3abc if a = -1, b = 2, c = 3 is 34.

→ In this question, a, b and c are variables. They can take any value and the answer will different in each case.