(II) A bag contains 6 green balls, some black and red balls. Number of blackballs is as twice as the number of red balls. Probability of getting a green ball is thrice theprobability of getting a red ball. Find
(i) number of black balls.
(ii) total number of balls.
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Answer:
Let , red balls = x
black balls = 2x
Total no.of balls = 6
probability of getting green balls = 6 / (6x+3)
probability of getting red balls = x / (6x+3)
On solving ,
x = 2
then ,
(i) No.of black balls = 2x
= 2(2) = 4
(ii) Total no.of balls = 6 + 3x
= 6 + 3(2)
= 6 + 6 = 12
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