Question

(ii) (a + bc)(a - bc) (a² + b²c²) plz answer in detail ​

Answer 1

Answer:

The answer would be 2a².

Step-by-step explanation:

You must know the formula:

(a+b)(a-b) = a²-b²

[when there are no sign between terms then there is multiplication between the terms]

so, (a+bc)(a-bc) (a²+b²c²)

= [(a)²-(bc)²] (a²+b²c²)

= (a²-b²c²) (a²+b²c²)

= 2a² (removing the brackets)

I hope it was helpful.

Answer 2

Answer:

a⁴ - b⁴c⁴

Step-by-step explanation:

(a + bc)(a - bc)(a² + b²c²)

stage : 1 : (a + bc)(a - bc)

$a ^{2} - b ^{2} = (a + b)(a - b)$

: (a² - b²c²)

stage :2 : (a² + b²c²)(a² - b²c²)

: (a⁴ - b⁴c⁴)