(ii) A car covers a distance of 270 kms with some speed. If the speed is
decreased by 10 km/hr, it will take 54 minutes more to cover the same
distance. Find the original speed of the car.(solve)
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Answer:
Let the speed of car is x.
Speed of carbon speed is decreased by 10 Km/hour = x-10.
= 270/x-10 - 270/x =54/60.
= 1/x-10 - 1/x = 54/60 X 270.
= x-x + 10/x(x-10) = 1/300
= 10 X 300 = x^2 - 10 x
= x^2 - 10 x -3000 = 0
= x^2 - 60 +50x-3000=0
= x (x-60) +50(x-60)=0
= (x-60) (x+50) = 0
THEREFORE,
(x-60)=0
So , x= 60 km/h
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