Question

II.A car starts from rest and
accelerates uniformly to a speed
50ms
over a distance of 250 m.
Find the acceleration and
time taken by the car to
cover this distance.​

Answer 1

GIVEN:-

• $\sf\pink{Initial\:velocity=0}$

• $\sf\blue{Final\:velocity=50m/s^{-1}}$

• $\sf\red{Distance\:travelled=250m}$

TO FIND:-

• Acceleration produced by car and time taken by car to cover distance

Using third equation of motion i.e.

$\huge\bigstar{\boxed{\sf{\blue{V^{2}-U^{2}=2as}}}}$

Put the values.

$\implies\sf\red{(50)^2-(0)^2=2×a×250}$

$\implies\sf\blue{2500-0=500a}$

$\implies\sf\pink{a=\dfrac{\cancel{2500}}{\cancel{500}}}$

Thus, The acceleration produced by car is 5m/s^2.

Now,

Using first equation of motion

$\huge\bigstar{\boxed{\sf{\blue{V=u+at}}}}$

$\implies\sf\red{50=0+5×t}$

$\implies\sf\blue{t=\frac{\cancel{50}}{\cancel{5}}}$

Thus the time taken by car is 10s.