Question

ii.
A charge + exerts a force of magnitude
-0.2 N on another change -2q. If they
are separated by 25.0 cm, determine the
value of q.​

Answer 1

Answer:

8.33*10^-7

Explanation:

use the formula of electrostatic force

F= Kq1q2/r^2

distance between them is 25cm=.25m

Answer 2

The value of charge is $8.33\times 10^{-7}\ C$.

Explanation:

Let +q and -2q are two charges.

The electric force between charges, F = - 0.2 N

Distance between charges, r = 25 cm = 0.25 m

The electric force between charges is given by :

$F=\dfrac{kq_1q_2}{r^2}$

$q_1q_2=\dfrac{Fr^2}{k}$

$2q^2=\dfrac{0.2\times (0.25)^2}{9\times 10^9}$

$q=\sqrt{6.94\times 10^{-13}}$

$q=8.33\times 10^{-7}\ C$

So, the value of charge is $8.33\times 10^{-7}\ C$. Hence, this is the required solution.

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