Question

(ii) A chord AC of a circle of radius 10cm makes a right angle at the centre.
Find the area of the minor sad sajor segments of the circle. (* 3.14)​

Answer 1

Answer:

A chord AC of a circle of radius 10cm makes a right angle at the centre.

So the length of the chord is =

$10 \sqrt{2} \: cm$

The area of the minor segment,

$\pi \: {r}^{2} \times \frac{90}{360} \\ = \frac{1}{4} \times \frac{22}{7} \times 100 \\ = 78.57 \: {cm}^{2}$

And area of major segments of the circle.

$\pi \: {r}^{2} \times \frac{270}{360} \\ = \frac{3}{4} \times \frac{22}{7} \times 100 \\ = 235.714 \: \: {cm}^{2}$