Question

ii) A converging mirror forms a real image of height 4 cm of an object of height 1 cm placed 20 cm away from the mirror.
a) Calculate the image distance
b) What is the focal length of the mirror?
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Answer 1

Answer:

h2 = - 4 cm (real iamge)

h1 = 1 cm

u = - 20 cm

(i) v = ?

m = h2/h1 = - (v/u)

⇒ -4/1 = -(v/-20)

⇒ v = -80 cm

Image forms in front of the concave mirror.

(ii) f = ?

1/v + 1/u = 1/f

1/-80 + 1/-20 = 1/f

1/f = - (1/80) – 1/20 = (-1 – 4)/80 = - (5/80)

f = - 16 cm

Answer 2

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