Question

ii) A force of 6N is applied on a body of mass 1Kg at rest. The body displaces by a
distance of 3m. Calculate the kinetic energy of the body.
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Answer 1

Explanation:

(ii)

Given,

Force(F)=6N

Mass(M)=1kg

velocity(V)=3m

Therefore the kinetic energy of the body =½mv²

=½×1×(3)²

=½×9

=4.5J