Question

(ii) A ladder 9 m long leaned against a wall. The ladder reaches the wall to a

height of 7.2 m. Find the distance between the wall and the foot of the ladder
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Answer 1

Answer:

It is given that

Length of ladder =6 m

Ladder reaches the wall to a height of 4.8 m

Consider AB as the ladder and AC as the height of the wall

AB=6 m and AC=4.8 m

Distance between the foot of ladder and wall is BC

Using Pythagoras theorem,

AB

2

=AC

2

+BC

2

Substituting the values

6

2

=4.8

2

+BC

2

By further calculation

BC

2

=6

2

−4.8

2

BC

2

=36−23.04=12.96

So we get

BC=√12.96=3.6 m

Hence, the distance between the wall and the foot of the ladder is 3.6 m.