Question

(ii) A man is 3(1/2) times as old as his son. If the sum of the squares of their ages is 1325, find the ages of the father and the son.​

Answer 1

Answer:

son age=x

A man age=3(1/2)x

according to question

(x)^2+(3(1/2))^2=1325

x^2+(7/2)^2=1325

x^2+49/4=1325

x^2=1325X4/49

x^2=5408/49

(x)^2=(73.53/7)^2

x=73.53

age of son=$73\sqrt{x}$

father age=$257 \sqrt{x}$sq

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