Math, asked by tirkeyarpna2, 1 day ago

(ii) A man is 42 years old and his son is 12 years old. How many years ago was the father's age six times that of the son? ​

Answers

Answered by crankybirds31
3

Answer:

"Let before x years, father's age was six times son's age.

Before x years their age was,

Father’s age = 42-x

Son's age = 12-x

Now, according to question,

42-x = 6*(12-x)

42-x = 72–6x

-x +6x = 72–42

5x= 30

x=6

Hence before 6 years father's age was six times son's age

We can verify also

42–6 = 36. Father's age

12–6 = 6. son's age

6*6=36

Hence the answer is 6. "

Similar questions
Math, 8 months ago