Question

(ii) A parallel plate capacitor is immersed in an oil of dielectric constant 2. The field
between plates :
(A) increases proportional to 2 (B) decreases proportional to 1/2
(C) increases proportional to
(D) decreases proportional to​

Answer 1

$\Large\underline{\underline{\sf Given:}}$

• Dielectric Constant of oil (K)=2

$\Large\underline{\underline{\sf To\:Find:}}$

• Electric Field between plates.

$\Large\underline{\underline{\sf Formula\:Used:}}$

$\large{\boxed{\boxed{\sf \pink{E=\dfrac{\sigma}{E_oK}}}}}$

E = Electric Field

$\sigma$ = Charge Density (Constant)

K = Dielectric Constant

$\Large\underline{\underline{\sf Solution:}}$

Electric filed of parallel plate capacitor is inversely proportional to $\bf{E_o}$

When ,

parallel plate capacitor is immersed in an oil of dielectric constant 2

then,

$\implies{\sf E=\dfrac{\sigma}{E_o×2 }}$

$\implies{\sf E\:\:\:\alpha\:\:\:\dfrac{1}{2} }$

$\Large\underline{\underline{\sf Answer:}}$

Option (b) Decreases and proportional to ½

${\sf E\:\:\:\alpha\:\:\:\dfrac{1}{2}}$