Question

(ii) (a2+ab+bº):(a2-ab+b2) = (c2+cd+d):(c2-cd+d?)​

Answer 1

Step-by-step explanation:

a²+ab+b²(c²-cd+d)=a²-ab+b²(c²+cd+d)

a²c²-a²cd+a²d+abc²-abcd+abd+b²c²-b²cd+b²d=a²c²+a²cd+a²d-abcd-abc²-abd+b²c²+b²cd+b²d

-a²cd+abc²+abd-b²cd=a²cd-abc²-abd+b²cd

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