Question

(ii) AABC - ALBN. In AABC, AB = 5.1 cm, 2B-40°, BC = 4.8 cm.
AC 4
LN7
Construct AABC and ALBN.​

Answer 1

Answer:

Given:

ΔABC∼ΔLBN.

In ΔABC,AB=5.1cm

∠B=400,BC=4.8cm,LNAC=74

Let

steps for constructing ΔABC∼ΔLBN

Step-1: Draw ΔABC such that AB=5.1cm

∠B=40,BC=4.8cm

Step-2: Divide segment BC into 4 equal parts

Step-3: Make point Non ray BC such that length of BN is seven times of each part of segment BC.

Step-4: Draw a line parallel to side AC, through N. Name the point where the parallel line intersects ray BA as 1

Hence, here  ΔABC∼ΔLBN