Question

(ii) AD is drawn perpendicular to BC, base of an
equilateral triangle ABC. Given BC=10 cm, find
the length of AD, correct to 1 place of decimal.
​

Answer 1

Answer:AD=8.66(or)8.7

Step-by-step explanation:

as it is a equilateral triangle AB=BC=10

And we know BD=DC=5 (AD is also a perpendicluar biscetor)

in right angle triangleABD

AB^2=BD^2+AD^2

10^2-5^2=AD^2

100-25=AD^2

AD=75^(0.5)

AD=8.66