Question

(ii)Alpha = 2+under root 3 , bita = 2-underoot 3

find the quadratic equations whose zeroes are given below​

Answer 1

Answer:

α = 2+√3 , β = 2-√3

α+β = 2+√3+2-√3 = 4

αβ = (2+√3)(2-√3)

= 4-3 = 1

quadratic equ,

x²-(α+β)x+αβ = 0

x²-4x+1 = 0