Question

(ii) An object is thrown vertically upwards and
rises to a height of 45 m. Calculate
[Take, g = 10 m/s]
[3]
(a) The velocity with which the object wa
thrown upward.
(b) The time taken by object to reach highes
point.
(c) Total time for which object remains in air​

Answer 1

s=45m

g=10m/s²

u=0

1: v²-u²=2as

v²-0²=2*10*45

v²=20*45

v²=900

v=30m/s

2: v=u+at

t=v-u/a

t=30/10

t=3sec. time to reach highest point

3: total time

here s is two time

s=ut+1/2at²

90=0+5t²

18=t²

t=9sec

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