Question

ii) At what temperature will the reading on the Fahrenheit scale be five
times of that on the Celsius scale?
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Answer 1

Answer:

Explanation:

C = 5/9(F-32) or (F-32)/1.8

We want C = 2F or F = C/2

So C = (C/2 - 32)/1.8

1.8 C = C/2 - 32

1.3 C = -32

C = -24.6, F = -12.3

-24.6 degrees C = -12.3 degrees F. That’s rounded to the nearest tenth of a degree.

At what temperature the Fahrenheit scale reading equal to half of Celsius scale:

Basic conversion formula: F = 9/5C + 32

Our problem: 2C = F

Substitute F in the first formula with 2C from the second, which gives you:

2C = 9/5C + 32

Subtract 9/5C from both sides, which gives:

2C - 9/5C = 32

Simplify the left side (2C = 10/5C): 10/5C - 9/5C = 32, which equals 1/5C = 32

Multiply 5 to each side, which leaves C = 160

ARMYYY