Question

(ii) Calculate the molecular weight of Na2CO3.10H20
(Na = 23; O = 16; C = 12; H = 1]​

Answer 1

Answer:

127u

Explanation:

(Na + 2×C + 3×O)+(10×H + 2×O)

= (23+14+48)+(10+32)

=85+42

=127u

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Answer 2

Answer: The correct answer is 127 u

Explanation:

The molecular weight can sometimes be considered as a molecular mass which is the mass of the given molecule and it is measured in the unit daltons and in the same compound  different molecules are there and different molecules have different masses because they have elements of different isotopes so molecular masses depend on the isotopes of the element and the sum of all these molecular masses or atomic masses  is called as the molecule weight, for example, the atomic mass of different elements are 1 for hydrogen then 12 for carbon than 14 for nitrogen and 18 for oxygen respectively and the molecular weight is also the mass of substance based on their atomic masses and atoms present in the molecule so according to the question

Given = molecule is Na2CO3.10H2O

where Na is 23

O is 16 and

carbon is 12 and

hydrogen is 1

Solution =  (Na + 2×C + 3×O) + (10×H + 2×O)

= (23+14+48)+(10+32)

=85+42

=127u

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