(ii) Calculate the number of moles of oxygen
present in the above volume and also the
number of molecules.
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At STP, 22.4 l of a gas = 1 mole.
6.72 l = (1 x 6.72)/22.4 = 0.3 moles.
One mole contains = 6 x 1023 molecules.
0.3 mole contains = 6 x 1023 x 0.3.
= 1.8 x 1023 molecules.
6.72 l of oxygen contains 0.3 moles and hence 1.8 x 1023 molecules.
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