Question

(ii) Calculate the standard enthalpy change and standard internal energy change for the
following reaction at 300K:
OF2 (g) +H2O(g)
O2(g) +2HF(g)
Given A/Hº(KJ per mole): OF2 (g) = 23.0; H20 (g) = -241.8; HF (g) = -268.6
R= 8.314 J/K/mole
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Answer 1

Answer:

578/10 J/K mole

Explanation:

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