Question

II Call lie weight of an object be zero?
A solid body of density 5000 kg/m weighs 5N in air. It is completely immersed in was
densitylg/cm
(a) Calculate the apparent weight of the soli in water.
(b) What would happen to the body if water is replaced by a liquid of density 8000 kgm.
Take
g= 10 m/s2.
10
That
i
n​

Answer 1

Answer:

Explanation:

apparent weight= w-u

u=VsPg

u=m/d*p*g

u=0.5/5000*1000*10

u=1

therefore apparent weight=5-1

=4 newtons

u=VsPg

u=0.5/5000*8000*10

u=8 newtons

apparent weight= w-u

=5-8

=-3

Here negative mass indicates

As compared to upthrust the downward is tending to 0

Here apparent weight is negative because

There is a huge difference between density of liquid and density of solid