ii) chlorine occurs in nature in two
isotopic form with masses 35u and 37
in the ratio 9:3, find average mass of cl
atom.
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Answer:
Explanation:
1st we have to find the % of two
isotopic form with masses
9x+3x=100
12x=100
x=100/12
x=8.3
therefore % isotopic form with mass 35u chlorine=9×8.3=74.7%
% isotopic form with mass 37u chlorine=3×8.3=24.9%
Avg At. mass of cl
atom.=35×74.7+37×24.9/100
=3535.8/100
=35.358 u
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