Question

(ii) Compute the percentage error in the time period T = 2 pi sqrt(1/g)
L= 1. If the error in the measurement of l is 0.01.​

Answer 1

Answer:

0.5%

Step-by-step explanation:

• T=2π√(l/g)

it can be written like these,

• T=2π(l/g)^(1/2)

therefore, error in time period(∆T/T) can be calculated by,

• ∆T/T=1/2×∆l/l. {since, all other quantities are constant, we have to consider only length}
• i.e, ∆T/T=(1/2)×(0.01/1)

=0.005

to find % error, we have to multiply it with 100

• ∆T/T×100=0.005×100

=0.5%

hope it helps..!