Question

(ii) cos 90° + cos²45° sin 30° tan 45°

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Answer 1

Answer:

cos 90°+cos²45°×sin 30°×tan 45°.

cos 90°=0.

cos²45°=(1/√2)²=1/2.

sin 30°=1/2.

tan 44°=1.

cos 90°+ cos²45°×sin 30°×tan 45°=0+(1/2)×(1/2)×(1).

cos 90°+cos²45°×sin 30°×tan 45°=0+(1/4)×(1).

cos 90°+cos²45°×sin 30°×tan 45°=0+1/4.

cos 90°+cos²45°×sin 30°×tan 45°=1/4.

I don't know trigonometry perfectly, then also I tried to solve it in my own way.

I think this is your answer.