Math, asked by anirudrapal, 4 days ago

ii. Determine the compound interest of Rs. 625 in 9 months at the rate of 10% per annum; interest being compounded quarterly​

Answers

Answered by mathdude500
12

\large\underline{\sf{Solution-}}

Given that,

Principal, P = Rs 625

Rate of interest, r = 10 % per annum compounded quarterly

Time, n = 9 months = 3/4 years

We know,

Compound interest ( CI ) on a certain sum of money of Rs P invested at the rate of r % per annum compounded quarterly for n years is given by

\boxed{\sf{  \: \: CI \:  =  \: P {\bigg[1 + \dfrac{r}{400} \bigg]}^{4n}  \:  -  \: P \:  \: }} \\

So, on substituting the values, we get

\rm \:   \: \: CI \:  =  \: 625{\bigg[1 + \dfrac{10}{400} \bigg]}^{3}  \:  -  \: 625 \:  \: \\

\rm \:   \: \: CI \:  =  \: 625{\bigg[1 + \dfrac{1}{40} \bigg]}^{3}  \:  -  \: 625 \:  \: \\

\rm \:   \: \: CI \:  =  \: 625{\bigg[ \dfrac{40 + 1}{40} \bigg]}^{3}  \:  -  \: 625 \:  \: \\

\rm \:   \: \: CI \:  =  \: 625{\bigg[ \dfrac{41}{40} \bigg]}^{3}  \:  -  \: 625 \:  \: \\

\rm \:   \: \: CI \:  =  \: 673.06  \:  -  \: 625 \:  \: \\

\rm\implies \:CI \:  =  \: 48.06 \\

Hence,

\rm\implies \:  \: \boxed{\sf{  \: \:  \:CI \:  =  \: Rs \: 48.06  \:  \: }}\\

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Additional Information :-

1. Amount on a certain sum of money of Rs P invested at the rate of r % per annum compounded annually for n years is given by

\boxed{\sf{  \: \: Amount \:  =  \: P {\bigg[1 + \dfrac{r}{100} \bigg]}^{n}  \:   \:  \: }} \\

2. Amount on a certain sum of money of Rs P invested at the rate of r % per annum compounded semi - annually for n years is given by

\boxed{\sf{  \: \: Amount \:  =  \: P {\bigg[1 + \dfrac{r}{200} \bigg]}^{2n}  \:   \:  \: }} \\

3. Amount on a certain sum of money of Rs P invested at the rate of r % per annum compounded quarterly for n years is given by

\boxed{\sf{  \: \: Amount \:  =  \: P {\bigg[1 + \dfrac{r}{400} \bigg]}^{4n}  \:   \:  \: }} \\

4. Amount on a certain sum of money of Rs P invested at the rate of r % per annum compounded monthly for n years is given by

\boxed{\sf{  \: \: Amount \:  =  \: P {\bigg[1 + \dfrac{r}{1200} \bigg]}^{12n}  \:   \:  \: }} \\

Answered by kvalli8519
6

Refer the given attachment

Attachments:
Similar questions