Question

ii) Determine the equation of the line passing
through A and perpendicular to
4x - 3y + 12 = 0 (ICSE 1997)​

Answer 1

Answer:

Given a line is perpendicular to the line 4x-3y=18

Now, slope of the above line is m =4/3

Let the slope of perpendicular line be m1

then m1 m = -1

=m1 = -3/4.

Then the equation with slope will be y = -3/4x+c

The above line is passing through

=3= -3/4x2+c

=c= 9/2

Therefore the required equation of line is y= -3/4x+9/2

4y+3x=18.

Step-by-step explanation:

hope it will you help you.