Physics, asked by studytarim1, 17 hours ago

(ii) Determine the magnitude of vector A = 2i - 3j​

Answers

Answered by samburajesh01234
0

Answer:

13 is the magnitude of the vector

Answered by Anagh7678
1

Solution :-

The magnitude of A = \bf{\rigtharrow\:\:\sqrt{(2)^2+(3)^2}}

\bf{\rightarrow\:\:\sqrt[2]{2^2+3^2}

\bf{\rightarrow\:\:\sqrt[2]{4+9}

\bf{\rightarrow\:\:\sqrt[2]{13}

Final Answer :-

The magnitude of vector A = 2i - 3j​ is √13.

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\bf{\rightarrow\:\:ANAGH

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