Question

ii) Determine the nature of the roots : 2x^2 + x-1 = 0

Answer 1

Answer:

Answer:

D =b2-4ac

Step-by-step explanation:

2*2-4*1*2

4-4

roots are real and equal

Answer 2

Answer:

The given equation have two real and distinct roots.

Step-by-step explanation:

Given : 2x² + x - 1 = 0

Here, a (coefficient of x²) = 2

         b (coefficient of x) = 1

         c (constant term) = -1

Discriminant = b² - 4ac

D = b² - 4AC

• If D > 0; When D is positive and greater than 0, the equation will have two real and distinct roots.
• If D = 0; When D is equal to zero, the equation will have two real and equal roots.
• If D < 0: When D is negative, the equation will have no real roots.

Here, D = (1)² - 4 × (2) × (-1)

         D = 1 + 8

         D = 9 > 0

      ∵ D > 0

∴ The given equation have two real and distinct roots.