Question

(ii) Determine whether the values given against the quadratic equation are the
roots of the equation or not.
x² + 4x - 5=0. x=1, - 1.​

Answer 1

Step-by-step explanation:

x ^ 2 + 4x -5 = 0

when x = 1

(1)^ 2 + 4( 1 ) - 5 = 0

1+ 4 -5 = 0

5- 5= 0

0= 0 hence 1 is root of the equation..

when x = -1

(-1)^2 + 4(-1) - 5 = 0

1 -4-5 = 0

-8 not equal to zero. hence -1 is not the root of this quartartic equation.....

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