Question

ii)Draw a circle and mark


a. pair of radii OA, OB

b. Sector XOY


( WANT STEP BY STEP EXPLANATION WITH THE CIRCLE AND THE ANSWERS )​

Answer 1

Step-by-step explanation:

In figure,

In angle AOPAOP and angle OBPOBP

Where,

 OAOA is equal to OBOB and they are the radius of the circle.

In circle OPOP is common for both the angle

So,

 OP=OPOP=OP (common)

Also,

Angle AA is equal to angle BB and they both are right angle triangle.

So,

 ∠A=∠B=90∘∠A=∠B=90∘

 ⇒⇒ by all the condition, we get

 ΔOAP≅ΔOBPΔOAP≅ΔOBP

Similarly,

 PA=PBPA=PB (They are equal tangents of the circle)

And ∠AOP=∠BOP=60∘∠AOP=∠BOP=60∘

Hence OPOP is a bisector of ∠BOA∠BOA .