Question

ii) Factorise: 15x⁴Y³ - 20 x³y​

Answer 1

Answer:

$\huge\boxed{15x^4y^3-20x^3y=5x^3y(3xy^2-4)}$

Step-by-step explanation:

$15x^4y^3-20x^3y\\\\15x^4y^3=\boxed{5}\cdot3\cdot\boxed{x^3}\cdot x\cdot\boxed{y}\cdot y^2\\20x^3y=\boxed{5}\cdot4\cdot\boxed{x^3}\cdot\boxed{y}\\\\15x^4y^3-20x^3y=\bigg(\boxed{5}\cdot\boxed{x^3}\cdot\boxed{y}\bigg)(3\cdot x\cdot y^2)-\bigg(\boxed{5}\cdot\boxed{x^3}\cdot\boxed{y}\bigg)(4)\\\\=\bigg(\boxed{5}\cdot\boxed{x^3}\cdot\boxed{y}\bigg)(3xy^2-4)$

Used:

$a^n\cdot a^m=a^{n+m}\\\text{distributive property}:\ a(b+c)=ab+ac$