Physics, asked by kuldeepv738, 7 months ago

(ii) Find out the angle of minimum deviation for equilateral prism if angle of
incidence and emergence is 48degree

Answers

Answered by lohithpatnaik773
0

Answer:

The emergence angle is 48°.

(I). The angle of deviation will be less than 36°.

(II). The angle of deviation will be more than 36°.

Explanation:

Given that,

Incident angle = 48°

Deviation angle = 36°

Prism is equilateral.

So, angle is 60°

We need to calculate the angle of emergence

Using formula of emergence angle

\delta=(i_{1}+i_{2})-Aδ=(i

1

+i

2

)−A

Where, i_{1}i

1

= incidence angle

\deltaδ = deviation angle

Put the value into the formula

36=48+i_{2}-6036=48+i

2

−60

i_{2}=48^{\circ}i

2

=48

The emergence angle is 48°.

(b). If the angle of incidence is changed

(I). Incidence angle is 30°

We need to deviation angle

Using formula of deviation

\delta=i_{1}+i_{2}-Aδ=i

1

+i

2

−A

Put the value into the formula

\delta=30+48-60δ=30+48−60

\delta=18^{\circ}δ=18

The angle of deviation will be less than 36°.

(II). Incidence angle is 60°

We need to deviation angle

Using formula of deviation

\delta=i_{1}+i_{2}-Aδ=i

1

+i

2

−A

Put the value into the formula

\delta=60+48-60δ=60+48−60

\delta=48^{\circ}δ=48

The angle of deviation will be more than 36°.

Hence, The emergence angle is 48°.

(I). The angle of deviation will be less than 36°.

(II). The angle of deviation will be more than 36°.

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