Question

(ii) find the angle of a parallelogram ABCD in which ZA =2Zb​

Answer 1

Answer:

$in \: prallelogram \: abcd \\ angle \: a = 2angle \: b \\either \: they \: would \: be \: opposite \: angles an \: opposite \: angles \: of \\ parallelogram \: are \: supplementary\\ or \\ they \: will \: form \: linear \: pair \\ now \\ angle \: a + \: angle \: b = 180 \\ angle \: a + \: 2angleb = 180 \\ 3angle \: a = 180 \\ angle \: a = 60 \\ hence \: angle \: a = 60 \: and \: angle \: b = 2angle \: a \\ angle \: b = 2 \times 60 \\ angle \: b = 120$