Math, asked by amipandey4444, 7 months ago

(ii) Find the direction cosines of the normal to
the plane 2 x - 3y +62 +14 = 0.

Answers

Answered by shriramkulkarni8669

2

2X - 3y = -76

2X-3y +62 + 14 = 0

2X-3y + 76 =0

2X-3y =-76

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