Question

ii) Find the equation of the straight line passing through the point of intersection of the lines x + y + 1 = 0 and 2x – y + 5 = 0 and containing the point (5,-2).
plz answer chapava​

Answer 1

Answer:

x−2y−a=0.....(i)

x+3y−2a=0....(ii)

equation of line passing through point of intersection of given lines is 

x−2y−a+λ(x+3y−2a)=0(1+λ)x+(3λ−2)y−(1+2λ)a=0......(i)

Slope of line =m=−ba=−3λ−21+λ

3x+4y=0......(ii)

Slope of (ii) =m′=−ba=−43

Both the lines are parallel

⇒m=m′−3λ−21+λ=−434+4λ=9λ−610=5λ⇒λ=2

Substituting λ in (i)

(1+2)x+(3(2)−2)y−(1+2(2))a=03x+4y−5a=