Question

ii) Find the locus of the third vertex of a right
angled triangle, the ends of whose
hypotenuse are (4,0) and (0,4).​

Answer 1

Answer:

Let P (x, y) be the point.

Slope of 1st side = (y-4)/x.

Slope of 2nd side = y/(x-4).

By this property,

y (y-4)/x (x-4) = -1.

y^2-4y = 4x-x^2.

x^2 + y^2 - 4x - 4y = 0 is a locus of required points.

Step-by-step explanation:

I hope it help you.