Question

(ii) For which value of k will the following pair of linear equations have no solution?
3x + y = 1
(2k-1) x + (k-1) y = 2k + 1​

Answer 1

Answer:

3x+y=1.

3x+y-1=0.

(2k-1)x+(k-1)y=2k+1.

(2k-1)x+(k-1)y-(2k+1)=0.

a1=3, a2=(2k-1).

b1=1, b2=(k-1).

c1=-1, c2=-(2k+1).

a1/a2=b1/b2≠c1/c2.

3(k-1)=1(2k-1).

3k-3=2k-1.

3k-2k=-1+3.

k=2.

I think this is your answer.